If it's not what You are looking for type in the equation solver your own equation and let us solve it.
6t^2+13t-28=0
a = 6; b = 13; c = -28;
Δ = b2-4ac
Δ = 132-4·6·(-28)
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{841}=29$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-29}{2*6}=\frac{-42}{12} =-3+1/2 $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+29}{2*6}=\frac{16}{12} =1+1/3 $
| 3x9x=3 | | 12-3m=-18 | | 35(2c+3)=2(c+6)+c | | 4(2y)+5y=65 | | |3x+7|=|3x+11| | | 7+4x=x-5 | | 14x+-5=7+11x | | 12+7r=r-6 | | (2x+10)x=170 | | (-2/3)x+53=59 | | 8x-1(6x-2)=-2 | | 1/8(p+24)=9 | | -a+6-5a=-2(a+3) | | x^2+7x+60=180 | | 6+3=5x+10 | | 7m=1/8 | | 9s+7s=-16 | | -4/9k=-1/5 | | 2.5x-5+3x+8=18.5 | | 9n135=15 | | -5q–-6q=18 | | 5(m-7)-8=-40+8m | | 8x+12(12)=256 | | 4/9+4(x-1)=289-(x-7x)+1 | | -1+3(x+4)=-10x-15 | | 3x^2+3x−90=0 | | 0.04x+0.03(1500-x=49 | | -1x+5=8.5 | | (2x+17)+(5x-40)=180 | | -28=-8v+6(v-7) | | -21=3/13x | | 2m11=135 |